The equation of line *a* is _{}.
If line *m* has a negative reciprocal slope to line *a* and passes through point (2, –4) what is the *y*-intercept of line *m*?

**(A)**–14

**(B)**–4.4

**(C)**–3.6

**(D)**4.4

**(E)**6

**Recognize the GMAT Topic Being Tested**

The question is testing knowledge of geometry, particularly coordinate plane geometry.

**Write Down the GMAT Information NOT Given in the Question**

The standard form for an equation of a line is

*y = mx + b.*

The coordinate point for the

*y*-intercept is defined as (0 ,

*y*).

**Connect the Information Not Given to the Information Given**

Because the equation given is not in standard form, we need to start by manipulating that equation to reflect standard form.le.

**Solve**

5

*x*=

*y*– 6

5

*x*+ 6 =

*y*

*y*= 5

*x*+ 6

Thus, the slope of line

*a*is 5 and the

*y*-intercept is 6.

Line

*m*has a slope of . Begin by creating the equation of line

*m*: .

**Rule: All points on a line will work in that lines equation.**

To find

*b*substitute the given point (2, –4) into the equation of line

*m*.

–4 = –0.2(2) +

*b*

–4 = –0.4 +

*b*

–3.6 =

*b*

**Reread the Question Asked and Select an Answer**

*Choose C.*

Do not neglect to reread the question, answering the wrong question is often a mistake the novice test-taker makes.